Variables in Hooke's Law Equation. F s = spring force. k = a spring constant. x = displacement. The equation can also be stated: F = kx F = k x. Where F is the force exerted on the spring, k is the spring constant and x is the displacement. You might see this equation in the case where the problem is in determining what is the force pulling on
3 feet and height h = 8 feet. Assummg the tank is full, find the work it takes to pump the water out of the tank. Note: weight density of water is pg = 62.51bs/ft3 10. A spherical tank of radius 4 m is half full of a liquid that has density of 900 kg per cubic meter. Find the work done in pumping the water through a spout
Use this calculator to determine the force applied to an object in newton, pound-force, kilogram-force or kilonewton units, to use a specified amount of energy or do work to move an object over a defined distance. Formula. The formula used by this calculator to determine the force exerted from the work done and distance moved is : F = W / d
So, in order to bring the object to rest i.e its same magnitude of energy is required so, as the final final energy comes to zero. v = 60km/hr =16.66m/s. So, magnitude of work that needs to be done = 1 2×m×v2. Hence, work required to stop the car = 1 2×1500 ×16.662 = 208166.7J = 208.17kJ.
The easiest way to calculate gravitational potential energy is to use our potential energy calculator. This tool estimates the potential energy on the basis of three values. These are: The mass of the object; Gravitational acceleration, which on Earth amounts to. 9.81 m / s 2. 9.81 \ \mathrm {m/s^2} 9.81 m/s2 or. 1 g.
View Solution. Q 5. A man weighing 80 kg carries a weight of 40 kg on the top of a tower 60 m high. Find the work done by the man. Take g = 10m/s2. View Solution. Click here:point_up_2:to get an answer to your question :writing_hand:a man weighing 70 kg carries a weight of 10 kg to top of a.
How much total work has been done on the block aft; A 5.0 kg box slides 8.0 m down a ramp, inclined at 40 degrees from the horizontal. If the box slides at constant velocity, find the work done by gravity. A 4.00-kg box of fruit slides 8.0 m down a ramp, inclined at 30.0 degrees from the horizontal.
A man weighing 50 kg lifts a weight of 30 kg to the top of building 10 m high. A man of mass 50 kg climbs up a ladder of height 10 m. Calculate: (i) the work done by the man, and (ii) the increase in his potential energy. Find the work done by the man. Take g = 10 m / s 2. View Solution. Q4. A man carrying a bag of mass 25 kg climbs up
Work is done when an object moves in the same direction as the force is applied and also when force remains constant. This online Work Calculator helps you find out the work, force or distance based on the other two parameters. Work, force and distance are related to each other.
Work Calculator How could this calculator be better? Soup Calculator Use This calculator will find the missing variable in the physics equation for Work, when two of the variables are known. Work Equation for these Calculations W = F s Where: W = Work F = Force s = displacement
a) potential energy acquired by the weight. b) work done by the weightlifter. Answer: Mass, m = 200 kg. Height, h = 2m. Acceleration due to gravity, g = 9.8 m/s2. a) Potential energy = mgh = 3920 J. b) Work done against gravity = potential energy gained by the weight. Therefore, work done, W = mgh = 3920 J. Long Answer Type Questions. Q52.
Box Ramp Work. In summary, to lift a 23kg box by a height of 1.0m, you would do 230J of work. If you choose to push the box up a 1.0m ramp at a 30 degree angle with no friction, you would need a force of 113N and the ramp would be 2m long. This results in the same amount of work being done, 230J, as the force and distance are still in the same
A) 360 J B) 180 J C) 90 J D) 0 J, You lift a 10-N physics book up in the air a distance of 1.0 m, at a constant velocity of 0.50 m/s. What is the work done by the weight of the book? A) +10 J B) -10 J C) +5.0 J D) -5.0 J, A 500-kg elevator is pulled upward with a constant force of 5500 N for a distance of 50.0 m.
Nov 24, 2016. Ramp Work Work done. In summary, a man weighing 85 kg pushes a crate 4.00 m up a ramp at a 20 degree angle to the horizontal with a force of 500N, resulting in a negative magnitude. To determine the work done, the x and y components of the forces acting on the man are set up and the force applied is found to be parallel to the ramp.
How much work is done by the force ; To push a 25-kg crate up a 27 ? incline, a worker exerts a force of 120 N, parallel to the incline. As the crate slides 3.6 m, how much work is done on the crate by (a) the worker, (b) the force of g; Calculate the work done by the force of gravity on the stone when it strikes the ground.
. 1a0ot3eiug.pages.dev/1841a0ot3eiug.pages.dev/1111a0ot3eiug.pages.dev/247